1. Chapter 6 Class 7 Triangle and its Properties
  2. Serial order wise
  3. Ex 6.5
Check sibling questions

Ex 6.5, 1 - Chapter 6 Class 7 Triangle and its Properties

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 6.5, 1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.In βˆ†PQR, right angled at P, PR = 24 cm, PQ = 10 cm, QR = ? By Pythagoras theorem, 〖𝑄𝑅〗^2 = 〖𝑃𝑄〗^2 + 〖𝑃𝑅〗^2 〖𝑄𝑅〗^2 = γ€–(10)γ€—^2 + γ€–(24)γ€—^2 〖𝑄𝑅〗^2 = 100 + 576 〖𝑄𝑅〗^2 = 676 〖𝑄𝑅〗^2 = γ€–(26)γ€—^2 Cancelling squares 𝑄𝑅 = 26 ∴ 𝑸𝑹 = 26 Rough 676 = 2 Γ— 2 Γ— 13 Γ— 13 = (2 Γ— 13) Γ— (2 Γ— 13) = 26 Γ— 26 = 262
  1. Chapter 6 Class 7 Triangle and its Properties
  2. Serial order wise

    3. Ex 6.5

    Examples →
Examples →
Chapter 6 Class 7 Triangle and its Properties
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo