Last updated at Dec. 16, 2024 by Teachoo
Example 3 Find the digits A & B Here, A × 3 ends with A We put different values of A, and check which ends with A ∴ A can be 0, or 5 Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible For A = 5 Calculating Multiplication Here, (3B + 1) + 5B ends with 7 i.e. 8B + 1 ends with 7 Checking different values of B ∴ B = 2 Checking for A = 5, B = 2 Putting values Hence verified ∴ A = 5 and B = 2
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo