1. Chapter 3 Class 7 Data Handling
  2. Serial order wise
  3. Ex 3.1
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Ex 3.1, 4 - Chapter 3 Class 7 Data Handling

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 3.1, 4 A cricketer scores the following runs in eight innings: 58, 76, 40, 35, 46, 45, 0, 100. Find the mean score Mean runs = (๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘Ÿ๐‘ข๐‘›๐‘ )/(๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘–๐‘›๐‘›๐‘–๐‘›๐‘”๐‘ ) = (58 + 76 + 40 + 35 + 46 + 45 + 0 + 100)/8 = 400/8 = 50 So, mean runs scored is 50
  1. Chapter 3 Class 7 Data Handling
  2. Serial order wise

    3. Ex 3.1

    Ex 3.2 →
Ex 3.2 →
Chapter 3 Class 7 Data Handling
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo