1. Chapter 8 Class 6 Decimals
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Example 3 - Chapter 8 Class 6 Decimals

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Example 3 Samson travelled 5 km 52 m by bus, 2 km 265 m by car and the rest 1km 30 m he walked. How much distance did he travel in all? Distance travelled by bus = 5 km 52 m Distance travelled by car = 2 km 265 m Distance travelled by foot = 1 km 30 m Total distance travelled = 5 km 52 m + 2 km 265 m + 1 km 30 m = (5 km + 52 m) + (2 km + 265 m) + (1 km + 30 m) = (5 km + 2 km + 1 km) + (52 m + 265 m + 30 m) = 8 km + 347 m = 8 km 347 m = 8 km 347 m Converting to decimals = 8 km + 347 m = 8 km + 347 × 1 m = 8 km + 347 × 1/1000 km = 8 km + 347/1000 km = (𝟖+𝟑𝟒𝟕/𝟏𝟎𝟎𝟎) km = ((8 × 1000 + 347)/1000) km = ((8000 + 347)/1000) km = 8347/1000 km = 8.347 km ∴ Total distance = 8.347 km
  1. Chapter 8 Class 6 Decimals
  2. Serial order wise

    3. Examples

    Place Value Table →
Place Value Table →
Chapter 8 Class 6 Decimals
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo