Question 1 - MCQ Questions - Chapter 2 - File Handling in Python

To open a file c:\scores.txt for reading, we use

Answer:

The syntax to open a file in python is as follows:

file_object= open(file_name, access_mode) 

Here, 

• the file_name will be c:\\scores.txt
• The file should be opened for reading ,  so access_mode is “r” .

Therefore, the correct answer will be

infile = open(“c:\\scores.txt”, “r”)

So, the correct answer is (b).