Ex 8.1, 9 (v) - Chapter 8 Class 7 Rational Numbers
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 8.1, 9 Which is greater in each of the following: (v) −3 2/7, −3 4/5 –3 𝟐/𝟕 = – (3+2/7) = – ((3 × 7 + 2)/7) = – ((21 + 2)/7) = (−23)/7 –3 𝟒/𝟓 = – (3+4/5) = – ((3 × 5 + 4)/5) = – ((15 +4)/5) = (−19)/5 So, we have to compare (−23)/7 & (−19)/5 Since both numbers are negative, We ignore the signs. 23/7 & 19/5 Comparing these two numbers Since denominator is different, We make same Common denominator = L.C.M of 5 & 7 = 5 × 7 = 35 So, 23/7 = 19/5 = Therefore, 115/35 < 133/35 i.e. 23/7 < 19/5 Multiplying –1 both sides 23/7 × –1 > 19/5 × –1 (−23)/7 > (−19)/5 –3 2/7 > –3 4/5 So, –3 𝟐/𝟕 is greater.
Ex 8.1
Ex 8.1, 1 (ii) Important
Ex 8.1, 1 (iii)
Ex 8.1, 1 (iv) Important
Ex 8.1, 2 (i)
Ex 8.1, 2 (ii) Important
Ex 8.1, 2 (iii)
Ex 8.1, 2 (iv) Important
Ex 8.1, 3 (i)
Ex 8.1, 3 (ii) Important
Ex 8.1, 3 (iii) Important
Ex 8.1, 4 (i)
Ex 8.1, 4 (ii)
Ex 8.1, 4 (iii) Important
Ex 8.1, 4 (iv) Important
Ex 8.1, 5
Ex 8.1, 6 (i) Important
Ex 8.1, 6 (ii)
Ex 8.1, 6 (iii)
Ex 8.1, 6 (iv) Important
Ex 8.1, 6 (v) Important
Ex 8.1, 6 (vi)
Ex 8.1, 6 (vii) Important
Ex 8.1, 7
Ex 8.1, 8
Ex 8.1, 9 (i) Important
Ex 8.1, 9 (ii)
Ex 8.1, 9 (iii) Important
Ex 8.1, 9 (iv)
Ex 8.1, 9 (v) Important You are here
Ex 8.1, 10
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo