The probability that a non leap year selected at random will contain 53 Sundays is
(A) 1/7 (B) 2/7
(C) 3/7 (D) 5/7
Last updated at Dec. 16, 2024 by Teachoo
Question 11 The probability that a non leap year selected at random will contain 53 Sundays is (A) 1/7 (B) 2/7 (C) 3/7 (D) 5/7 A non leap year has 365 days Dividing by 7 Number of weeks in non-leap year = 365/7 = ๐๐ ๐/๐ Thus, a non-leap year has 52 weeks, and 1 day extra That 1 extra day can be {Mon, Tues, Wed, Thur, Fri, Sat, Sun} Thus, Probability that a non leap year will contain 53 Sundays = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐๐๐๐ฆ ๐๐ ๐ ๐ค๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐๐ฆ๐ ๐๐ ๐ ๐ค๐๐๐) = ๐/๐ So, the correct answer is (A)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo