1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise
  3. Surface Area of Cylinder
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Question 8 - Surface Area of Cylinder - Chapter 11 Class 9 Surface Areas and Volumes

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Question 8 In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. [ = 22/7] The cylindrical pipe radiates from the curved surface & not from the ends So, we need to find curved surface area of cylinder Height (h) of cylindrical pipe = 28 m Radius (r) of circular end of pipe = 5/2 cm = 2.5 cm r = 2.5 1/100 m Total radiating surface in the system = CSA of cylindrical pipe = 2 rh = (2 22/7 0.025 28) m2 = 4.4 m2
  1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise

    3. Surface Area of Cylinder

    Volume of Cube and Cuboid →
Volume of Cube and Cuboid →
Chapter 11 Class 9 Surface Areas and Volumes
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo