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Question 4 The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2? [๐ด๐‘ ๐‘ ๐‘ข๐‘š๐‘’ ๐œ‹= 22/7] Roller is of form cylinder Radius = ๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ/2 = 84/2 = 42 cm Area of roller = Curved surface of cylinder = 2ฯ€rh = (2ร—22/7ร—42ร—120) cm2 = 31680 cm2 Area of 1 revolution = Area of roller = 31680 cm2 Area of 500 revolution = 500 ร— 31680 cm2 Area of playground = 15840000 cm2 = 15840000 ร—1/(100 ) ร—1/(100 )m2 = 1584 m2

  1. Chapter 11 Class 9 Surface Areas and Volumes
  2. Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo