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Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = ๐‘›๏ทฎ2๏ทฏ๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + ๐‘›๏ทฎ2๏ทฏ + 1๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 12๏ทฎ2๏ทฏ๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + 12๏ทฎ2๏ทฏ + 1๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 6๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + 7๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 13 + 14๏ทฎ2๏ทฏ = 27๏ทฎ2๏ทฏ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = ๏ทฎ๏ทฎ ๐‘ฅ๐‘– โˆ’M๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = 10 โˆ’ 13.5๏ทฏ + 11 โˆ’ 13.5๏ทฏ + 11 โˆ’ 13.5๏ทฏ + 12 โˆ’ 13.5๏ทฏ + 13 โˆ’ 13.5๏ทฏ+ 13 โˆ’ 13.5๏ทฏ๏ทฎ+ 14 โˆ’ 13.5๏ทฏ + 16 โˆ’ 13.5๏ทฏ + 16 โˆ’ 13.5๏ทฏ + 17 โˆ’ 13.5๏ทฏ + 17 โˆ’ 13.5๏ทฏ+ 18 โˆ’ 13.5๏ทฏ๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = โˆ’3.5๏ทฏ + โˆ’2.5๏ทฏ + โˆ’2.5๏ทฏ + โˆ’1.5๏ทฏ + โˆ’0.5๏ทฏ + โˆ’0.5๏ทฏ๏ทฎ+ 0.5๏ทฏ + 2.5๏ทฏ + 2.5๏ทฏ+ 3.5๏ทฏ + 3.5๏ทฏ + 4.5๏ทฏ ๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5๏ทฎ12๏ทฏ = 28๏ทฎ12๏ทฏ = 2.33

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.