Question 12 - Binomial Distribution - Chapter 13 Class 12 Probability
Last updated at April 16, 2024 by Teachoo
Binomial Distribution
Question 12 Deleted for CBSE Board 2024 Exams You are here
Question 2 Deleted for CBSE Board 2024 Exams
Question 4 Important Deleted for CBSE Board 2024 Exams
Question 9 Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 11 Deleted for CBSE Board 2024 Exams
Question 14 (MCQ) Important Deleted for CBSE Board 2024 Exams
Question 15 (MCQ) Important Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams
Question 13 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 10 Important Deleted for CBSE Board 2024 Exams
Question 5 Deleted for CBSE Board 2024 Exams
Question 10 Important Deleted for CBSE Board 2024 Exams
Question 1 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Misc 4
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 13 Deleted for CBSE Board 2024 Exams
Question 8 Deleted for CBSE Board 2024 Exams
Question 12 Deleted for CBSE Board 2024 Exams You are here
Binomial Distribution
Last updated at April 16, 2024 by Teachoo
Question 12 Find the mean of the Binomial distribution B(4, 1/3) B(4, 1/3) means Here, n = 4, p = 1/3 So, q = 1 − 1/3 = 2/3 Hence, P (X = x) = 4Cx (𝟏/𝟑)^𝒙 (𝟐/𝟑)^(𝟒−𝒙) Mean of distribution = P (X = x) = 4Cx (1/3)^𝑥 (2/3)^(4−𝑥) Mean = = 0 + 1 × 4C1 (1/3)^1 (2/3)^3+ 2 × 4C2 (1/3)^2 (2/3)^2 + 3 × 4C3 (1/3)^3 (2/3) + 4 × 4C4 (1/3)^4 (2/3)^0 = 4 × 1/3 × 8/27 + 2 × 6 × 1/9 × 4/9 + 3 × 4 × 1/27 × 2/3 + 4 × 1/3^4 × 1 = 32/81+48/81+24/81+4/81 = 108/81 = 𝟒/𝟑