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Transcript

Ex 3.1 , 7 Find the value of a, b, c, and d from the equation: [■8(a−b&2a+c@2a−b&3c+d)] = [■8(−1&5@0&13)] Since matrices are equal. Their corresponding elements are equal a − b = −1 2a − b = 0 2a + c = 5 3c + d = 13 Solving these equations From (2) 2a − b = 0 2a = b b = 2a Solving (1) a − b = −1 Putting b = 2a a − 2a = −1 –a = −1 a = 1 Now, we know b = 2a Putting a = 1 b = 2 (1) b = 2 Solving (3) 2a + c = 5 Putting a = 1 2(1) + c = 5 2 + c = 5 c = 5 – 2 c = 3 Solving (4) 3c + d = 13 Putting c = 3 3(3) + d = 13 9 + d = 13 d = 13 – 9 d = 4 Hence a = 1, b = 2, c = 3 & d = 4

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.