Ex 10.1, 5 - Find slope of a line, which passes through origin

Ex 10.1, 5 - Chapter 10 Class 11 Straight Lines - Part 2
Ex 10.1, 5 - Chapter 10 Class 11 Straight Lines - Part 3

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Ex 9.1, 5 Find the slope of a line, which passes through the origin, and the mid-point of the line segment joining the points P (0, –4) & B (8, 0). We need to find Slope of a line passing through origin O (0, 0) & mid point of P (0, –4) & B (8, 0) Let M be the mid point of P (0, –4) & B (8, 0) We know that mid point of (x1, y1) and (x2, y2) = ((𝑥1 + 𝑥2 )/2,(𝑦1 + 𝑦2)/2) Mid point M of (0, –4) & (8, 0) = ((0 + 8)/2, ( − 4 + 0)/2) = (8/2, (−4)/2) = (4, –2) We know that slope of line passing through (x1, y1) and (x2, y2) is m = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) Slope of line between points O (0, 0) & M (4, –2) Here, x1 = 0, y1 = 0 x2 = 4, y2 = –2 Putting values m = ( − 2 − 0)/(4 − 0) = ( −2)/4 = ( −1)/2 Hence slope of line is (−𝟏)/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.