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Ex 11.2, 4

Construct a triangle ∆XYZ in which ∠Y = 30° ∠Z = 90° and XY + YZ + ZX = 11 cm.

Steps of Construction:

  1. Draw a line segment PQ equal to XY + YZ + ZX = 11 cm.
  2. Make ∠ LPQ = ∠Y = 30° and ∠ MQP = ∠Z = 90°
  3. Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point X .
  4. Draw perpendicular bisectors of line XP and XQ
  5. Let AB intersect PQ at Y and CD intersect PQ at Z.
  6. Join XY and XZ

∴ Δ XYZ is the required triangle

-ev-

  1. Chapter 11 Class 9 Constructions
  2. Concept wise
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CA Maninder Singh is a Chartered Accountant for the past 7 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
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