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  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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Ex 11.2, 3 Construct a triangle PQR in which QR = 6 cm, ∠Q = 60°  and PR − PQ = 2 cm. Given that, In ∆PQR, QR = 6 cm, ∠Q = 60°  and PR − PQ = 2 cm. Steps of Construction Draw base QR = 6 cm and at point B make a ∠ XQR = ∠ Q = 60° Cut a line segment QD equal to PR – PQ from ray BX Join DR. Draw perpendicular bisector  AB of line DR. Let AB intersect QX a point P. Join PR. ∴ Δ PQR is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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