Ex 11.2, 2
Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm.
Given, in Δ ABC,
BC = 8 cm ∠B = 45° and AB – AC = 3.5 cm
Steps of Construction
- Draw base BC = 8 cm and at point B make an ∠ XBC = ∠ B = 45°
- Cut a line segment BD equal to AB – AC from ray BX
Join DC. Draw perpendicular bisector.
PQ of line DC.
- Let PQ intersect BX a point A. Join AC.
Then, Δ ABC is the required triangle.