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Example 13 - Solve 5x + 4y <= 40, x >= 2, y >= 3 graphically - Graph - 2 or more Equation

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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise
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Example 13 Solve the following system of inequalities graphically: 5x + 4y ≤ 40, x ≥ 2, y ≥ 3 First we solve 5x + 4y ≤ 40 Lets first draw graph of 5x + 4y = 40 Drawing graph Checking for (0,0) 5x + 4y ≤ 40 Putting x = 0, y = 0 5(0) + 4(0) ≤ 40 0 ≤ 40 which is true Hence origin lies in plane 5x + 4y ≤ 40 So, we shade left side of line Also, y ≥ 3 So, for all values of x , y = 3 Also, x ≥ 2 So, for all values of y , x = 2 Hence the shaded region represents the given inequality

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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