Ex 6.3, 14 - Solve graphically: 3x + 2y <= 150, x + 4y <= 80 - Graph - 2 or more Equation

Slide12.JPG
Slide13.JPG Slide14.JPG Slide15.JPG

  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise
Ask Download

Transcript

Ex 6.3, 14 Solve the following system of inequalities graphically: 3x + 2y 150, x + 4y 80, x 15, y 0, x 0 Now we solve 3x + 2y 150 Lets first draw graph of 3x + 2y = 150 Drawing graph Checking for (0,0) Putting x = 0, y = 0 3x + 2y 150 4(0)+ 3(0) 150 0 150 which is true Hence origin lies in plane 3x + 2y 150 So, we shade left side of line Now we solve x + 4y 80 Lets first draw graph of x + 4y = 80 Drawing graph Checking for (15,0) Putting x = 15, y = 0 y 2x 0 2(15) 0 30 which is false Hence (15,0) does not lie in plane y 2x So, we shade left side of line Also, x 15 So, for all values of y, x = 15 Given x 15, so we shade left side of line Also, given x, y 0 So, the shaded region will lie in 1st quadrant. Hence the shaded region represents the given inequality.

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.