Ex 6.3, 3 - Solve 2x + y >= 6, 3x + 4y <= 12 graphically   - Ex 6.3

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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise
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Ex6.3, 3 Solve the following system of inequalities graphically: 2x + y≥ 6, 3x + 4y ≤ 12 First we solve 2x + y ≥ 6 Lets first draw graph of 2x + y = 6 Drawing graph Checking for (0,0) Putting x = 0, y = 0 2x + y ≥ 6 2(0) + (0) ≥ 6 0 ≥ 6 which is false So, we shade right side of line Hence origin does not lie in plane 2x + y ≥ 6 Now we solve 3x + 4y ≤ 12 Lets first draw graph of 3x + 4y = 12 Drawing graph Checking for (0,0) Putting x = 0, y = 0 3x + 4y ≤ 12 3(0) + 2(0) ≤ 12 0 ≤ 12 which is true Hence origin lies in plane 3x + 2y > 6 . So, we shade left side of line Hence the shaded region represents the given inequality.

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