Ex 6.3, 2 - Solve 3x + 2y <= 12, x >= 1, y >= 2 graphically - Graph - 2 or more Equation

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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise
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Ex6.3, 2 Solve the following system of inequalities graphically: 3x + 2y 12, x 1, y 2 First we solve 3x + 2y 12 Lets first draw graph of 3x + 2y = 12 Drawing graph Checking for (0,0) Putting x = 0, y = 0 3x + 2y 12 3(0) + 2(0) 12 0 12 which is true Hence origin lies in plane 3x + 2y 12 So, we shade left side of line Also, y 2 So, for all values of x, y = 2 Also, x 1 So, for all values of y, x = 1 Hence the shaded region represents the given in equality

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.