# Misc 22

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 22 The normal at the point (1,1) on the curve 2 + 2 =3 is + = 0 ( ) = 0 ( ) + +1 = 0 ( ) = 1 Since (1, 1) lies on normal, it will satisfy its equation Option 1 Equation of Normal is + =0 Putting =1 & =1 in equation 1 +1=0 2=0 2 0 + =0 is not equation of Normal Option 2 If Equation of Normal is = 0 Putting =1 & =1 in equation =0 1 1=0 0=0 Since Point 1 , 1 Satisfying the Equation of Normal Hence, required Equation of Normal is =0 Option 3 If Equation of Normal is + +1=0 Putting =1 & =1 in equation + +1=0 1+1+1=0 3=0 But 3 0 + +1=0 is not Required Equation of Normal Option 4 If Equation of Normal is =1 Putting =1 & =1 in equation 1 1=1 0=1 But 0 1 =1 is not Required Equation of Normal Hence, Correct Answer is (B)

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Misc 22 Important You are here

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.