Ex 6.3, 4 - Find slope of tangent at y = x3 - 3x + 2 at x = 3 - Ex 6.3

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  1. Chapter 6 Class 12 Application of Derivatives
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Ex 6.3,4 Find the slope of the tangent to the curve 𝑦= 𝑥﷮3﷯−3𝑥+2 at the point whose 𝑥−coordinate is 3 𝑦= 𝑥﷮3﷯−3𝑥+2 We know that slope of tangent = 𝑑𝑦﷮𝑑𝑥﷯ 𝑑𝑦﷮𝑑𝑥﷯=3 𝑥﷮2﷯−3 Since 𝑥−coordinate is 3 Putting 𝑥=3 in (1) 𝑑𝑦﷮𝑑𝑥﷯│﷮𝑥 = 3﷯=3 3﷯﷮2﷯−3 =3 ×9−3 =27−3 =24 Hence slope of tangent is 24

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