Ex 13.2, 9 - If A and B are two events such that P(A) = 1/4, P(B) =1/4

Ex 13.2, 9 - Chapter 13 Class 12 Probability - Part 2

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 13.2, 9 If A and B are two events such that P (A) = 1/4 , P (B) = 1/4 and P(A ∩ B) = 1/8 , find P (not A and not B).Given, P(A) = 1/4 , P(B) = 1/2 & P(A ∩ B) = 1/8 P(not A & not B) = P(A’ ∩ B’) = P(A ∪ B)’ = 1 – P(A or B) = 1 – P(A ∪ B) = 1 – [P(A) + P(B) – P(A ∩ B)] = 1 – (1/4 " + " 1/2 – 1/8) = 1 – (2/8 " + " 4/8 – 1/8) = 1 – 5/8 = 𝟑/𝟖

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.