# Ex 13.2, 7

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 13.2, 7 Given that the events A and B are such that P(A) = 12 , P (A ∪ B) = 35 and P(B) = p. Find p if they are (i) mutually exclusive Given, P(A) = 12 , P (A ∪ B) = 35 and P(B) = p. Given sets A & B are mutually exclusive, So, they have nothing in common ∴ P(A ∩ B) = 0 We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values 35 = 12 + p – 0 35 – 12 = p 6 − 510 = p 110 = p p = 𝟏𝟏𝟎 Ex 13.2, 7 Given that the events A and B are such that P(A) = 12 , P (A ∪ B) = 35 and P(B) = p. Find p if they are (ii) independent. Since events A & B are independent, So, P(A ∩ B) = P(A) P(B) = 12 × p = 𝑝2 Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values 35 = 12 + p – 𝑝2 32 – 12 = p – 𝑝2 6 − 510 = 𝑝2 110 = 𝑝2 p = 210 p = 𝟏𝟓

Example 7
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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.