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Ex 13.1, 3 - If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4 - Conditional Probability - Values given

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  1. Chapter 13 Class 12 Probability
  2. Serial order wise
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Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (i) P(A ∩ B) P(A) = 0.8 , P(B) = 0.5 & P(B|A) = 0.4 Now, we know that P(B|A) = 𝑃(𝐵 ∩ 𝐴)﷮𝑃(𝐴)﷯ 0.4 = 𝑃(𝐴 ∩ 𝐵)﷮𝑃(𝐴)﷯ 0.4 = 𝑃(𝐴 ∩ 𝐵)﷮0. 8﷯ P(A ∩ B) = 0.4 × 0.8 P(A ∩ B) = 0.32 ∴ P(A ∩ B) = 0.32 Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (ii) P(A|B) P(A|B) = 𝑃(𝐴 ∩ 𝐵)﷮𝑃(𝐵)﷯ = 0.32﷮0.5﷯ = 32﷮50﷯ = 0.64 ∴ P(A|B) = 0.64 Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (iii) P(A ∪ B) P(A ∪ B) = P(A) + P(B) – P(A ∪ B) = 0.8 + 0.5 – 0.32 = 1.3 – 0.32 = 0.98 ∴ P(A ∪ B) = 0.98

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