# Misc 14

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 14 Define a binary operation *on the set {0, 1, 2, 3, 4, 5} as a * b = + , + <6 & + 6, + 6 Show that zero is the identity for this operation and each element a 0 of the set is invertible with 6 a being the inverse of a. e is the identity of * if a * e = e * a = a Now, we need to show that each element a 0 of the set is invertible with 6 a being the inverse of a. a * b = + , + <6 & + 6, + 6 An element a in set is invertible if, there is an element in set such that , a * b = e = b * a Putting b = 6 a So, a + b = a + (6 a) = 6 Since a + b 6 a * b = a + b 6 a * b = a * (6 a) = a + (6 a) 6 = 0 b * a = (6 a) * a = (6 a) + a 6 = 0 Since a * (6 a) = (6 a) * a = 0 Hence, each element a of the set is invertible with 6 a being the inverse of a.

Chapter 1 Class 12 Relation and Functions

Ex 1.2, 5
Important

Ex 1.2 , 10 Important

Example 23 Important

Example 25 Important

Ex 1.3, 3 Important

Ex 1.3 , 6 Important

Ex 1.3 , 8 Important

Ex 1.3 , 9 Important

Ex 1.3 , 13 Important

Ex 1.3 , 14 Important

Ex 1.4, 11 Important

Misc 3 Important

Misc. 4 Important

Misc 14 Important You are here

Misc 18 Important

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.