Ex 5.2, 3 - Differentiate sinโก (ax + b) - Chapter 5 Class 12 - Finding derivative of a function by chain rule

  1. Chapter 5 Class 12 Continuity and Differentiability
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Ex 5.2, 3 Differentiate the functions with respect to x sinโก(๐‘Ž๐‘ฅ + ๐‘) Let ๐‘“(๐‘ฅ) = sinโก(๐‘Ž๐‘ฅ + ๐‘) ๐‘ฆ = sin (๐‘Ž๐‘ฅ + ๐‘) We need to find derivative of ๐‘ฆ, ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘‘๐‘ฆ ๏ทฎ๐‘‘๐‘ฅ๏ทฏ = ๐‘‘ ( sin๏ทฎ(๐‘Ž๐‘ฅ + ๐‘)๏ทฏ) ๏ทฎ๐‘‘๐‘ฅ๏ทฏ = cos ๐‘Ž๐‘ฅ + ๐‘๏ทฏ ร— ๐‘‘ (๐‘Ž๐‘ฅ + ๐‘)๏ทฎ๐‘‘๐‘ฅ๏ทฏ = cos ๐‘Ž๐‘ฅ + ๐‘๏ทฏร— ๐‘‘(๐‘Ž๐‘ฅ)๏ทฎ๐‘‘๐‘ฅ๏ทฏ+ ๐‘‘(๐‘)๏ทฎ๐‘‘๐‘ฅ๏ทฏ๏ทฏ = cos ๐‘Ž๐‘ฅ + ๐‘๏ทฏ . (a + 0) = ๐’‚ ๐’„๐’๐’”โก(๐’‚๐’™ + ๐’ƒ)

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