Ex 5.4, 7 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at July 20, 2026 by

Ex 5.4, 7 - Differentiate root e root x - Chapter 5 NCERT

Ex 5.4, 7 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

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Ex 5.4, 7 Differentiate w.r.t. x in, āˆš(š‘’^āˆšš‘„ ), x > 0Let š‘¦ = āˆš(š‘’^āˆšš‘„ ) Differentiating both sides š‘¤.š‘Ÿ.š‘”.š‘„ š‘¦^ā€² = (āˆš(š‘’^āˆšš‘„ ))^ā€² š‘¦^ā€² = 1/(2 āˆš(š‘’^āˆšš‘„ )) Ɨ (š‘’^āˆšš‘„ )^ā€² š‘¦^ā€² = 1/(2 āˆš(š‘’^āˆšš‘„ )) Ɨ š‘’^āˆšš‘„ . Ɨ (āˆšš‘„)^ā€² š‘¦^ā€² = 1/(2 āˆš(š‘’^āˆšš‘„ )) Ɨ š‘’^āˆšš‘„ . Ɨ 1/(2āˆšš‘„) š‘¦^ā€² = š‘’^āˆšš‘„/(4āˆšš‘„ . āˆš(š‘’^āˆšš‘„ )) š‘¦^ā€² = š’†^āˆšš’™/(šŸ’āˆš(š’™ . š’†^āˆšš’™ ))

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