Question 3 - Remainder Theoram - Chapter 2 Class 9 Polynomials

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Question 3 (Method 1) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 Dividing 𝒙^𝟑+𝟏 by 𝒙+𝟏 Step 1: Putting Divisor = 0 x + 1 = 0 x = −1 Step 2: Let 𝑝(𝑥)=𝑥^3+1 Putting x = −1 𝑝(−𝟏)=〖(−𝟏)〗^3+1 =−1+1 =0 Thus, Remainder =𝒑(−𝟏)=𝟎 Question 3 (Method 2) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 By long division Hence, the remainder is 0