Ex 11.2, 7 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at April 16, 2024 by Teachoo
Ex 11.2
Ex 11.2, 1
Ex 11.2, 2
Ex 11.2, 3 Important
Ex 11.2, 4
Ex 11.2, 5 Important
Ex 11.2, 6
Ex 11.2, 7 Important You are here
Ex 11.2, 8 (i) Important
Ex 11.2, 8 (ii)
Ex 11.2, 9 (i) Important
Ex 11.2, 9 (ii)
Ex 11.2, 10 Important
Ex 11.2, 11
Ex 11.2, 12 Important
Ex 11.2, 13 Important
Ex 11.2, 14
Ex 11.2, 15 Important
Question 1 Important Deleted for CBSE Board 2024 Exams
Question 2 Deleted for CBSE Board 2024 Exams
Chapter 11 Class 12 Three Dimensional Geometry
Serial order wise
Transcript
Ex 11.2, 7 The Cartesian equation of a line is (𝑥 − 5)/3 = (𝑦 + 4)/7 = (𝑧 − 6)/2. Write its vector form.Cartesian equation : (𝑥 − 5)/3 = (𝑦 + 4)/7 = (𝑧 − 6)/2 (𝒙 − 𝟓)/𝟑 = (𝒚 − (−𝟒))/𝟕 = (𝒛 − 𝟔)/𝟐 Equation of a line in Cartesian form is given by (𝑥 − 𝑥1)/𝑎 = (𝑦 − 𝑦1)/𝑏 = (𝑧 − 𝑧1)/𝑐 Comparing (1) and (2), 𝒙1 = 5, 𝒚1 = −4, 𝒛1 = 6 𝒂 = 3, b = 7, c = 2 Equation of line in vector form is 𝒓 ⃗ = 𝒂 ⃗ + 𝜆𝒃 ⃗ Where 𝒂 ⃗ = 𝑥1𝑖 ̂ + y1𝑗 ̂ + z1𝑘 ̂ = 5𝒊 ̂ − 4𝒋 ̂ + 6𝒌 ̂ & 𝒃 ⃗ = 𝑎𝑖 ̂ + b𝑗 ̂ + c𝑘 ̂ = 3𝒊 ̂ + 7𝒋 ̂ + 2𝒌 ̂ Now, 𝑟 ⃗ = (5𝒊 ̂ − 4𝒋 ̂ + 6𝒌 ̂) + 𝜆 (3𝒊 ̂ + 7𝒋 ̂ + 2𝒌 ̂)
