# Example 34

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 34 Prove that Δ = a+bxc+dxp+qxax+bcx+dpx+quvw = (1 – x2) acpbdquvw Taking L.H.S Δ = a+bxc+dxp+qxax+bcx+dpx+quvw Applying R1 → R1 − xR2 = a+bx−𝑥 (𝑎𝑥+𝑏)c+dx−xp+qx−x (px+q)ax+bcx+dpx+quvw = a+bx−𝑎𝑥2 −𝑏𝑥c+dx−cx2−dxp+qx−px2−pxax+bcx+dpx+quvw = a−𝑎𝑥2 c−cx2p−px2ax+bcx+dpx+quvw = a (𝟏−𝒙𝟐) c(𝟏−𝐱𝟐)p(𝟏−𝐱𝟐)ax+bcx+dpx+quvw Taking (1 – x2) common from R1 = (1 – x2) acpax+bcx+dpx+quvw Applying R2 → R2 – xR1 = (1 – x2) acpax+b−xacx+d−cxpx+q−pxuvw = (1 – x2) acpbdquvw = R.H.S Hence Proved

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Example 18 Important

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Example 32 Important

Example 34 Important You are here

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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.