Ex 4.6, 3 - Examine consistency x + 3y = 5, 2x + 6y = 8 - Ex 4.6

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  1. Chapter 4 Class 12 Determinants
  2. Serial order wise
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Ex 4.6, 3 Step 2 Calculate |A| |A| = 1﷮3﷮2﷮6﷯﷯ = 1(6) – 2(3) = 6 – 6 = 0 Since |A| = 0, we will calculate (adj A) B A = 1﷮3﷮2﷮6﷯﷯ adj (A) = 1﷮3﷮2﷮6﷯﷯ = 6﷮−3﷮−2﷮1﷯﷯ Now, (adj A)(B) = 6﷮−3﷮−2﷮1﷯﷯ 5﷮8﷯﷯ = 6 5﷯+ −3﷯8﷮−2 5﷯+1(8)﷯﷯ = 30−24﷮−10+8﷯﷯ = 6﷮−2﷯﷯ ≠ O Since adj A (B) ≠ O & |A| = 0, , There exists no solution, Hence the given system of equation is inconsistent

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