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Ex 8.1, 4 Which term of the sequence 𝑑_𝑛=5π‘›βˆ’3 for 𝑛β‰₯1 is 607? To check which term is 607 of the sequence We put 𝑑_𝑛 = 607 and find n Given 𝒕_𝒏=πŸ“π’βˆ’πŸ‘ Putting 𝒕_𝒏 = 607 607 = 5n – 3 607 + 3 = 5n 610 = 5n 5n = 610 n = 610/5 n = 122 Thus, 607 is the 122nd term of the sequence

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