Exercise Set 8.1
Last updated at June 9, 2026 by Teachoo
Transcript
Ex 8.1, 4 Which term of the sequence π‘_π=5πβ3 for πβ₯1 is 607? To check which term is 607 of the sequence We put π‘_π = 607 and find n Given π_π=ππβπ Putting π_π = 607 607 = 5n β 3 607 + 3 = 5n 610 = 5n 5n = 610 n = 610/5 n = 122 Thus, 607 is the 122nd term of the sequence