Ex 11.2, 7 - Find equation of parabola: Focus (6,0), x = -6 - Parabola - Basic Questions

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise
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Ex 11.2, 7 Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = –6 Since focus lies on x-axis Hence equation is either y2 = 4ax or y2 = −4ax Now focus has positive x co-ordinate So, we have to use equation y2 = 4ax Coordinate of focus = (a, 0) (a, 0) = (6, 0) a = 6 Hence equation of parabola is y2 = 4ax y2 = 4(6)x y2 = 24x

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