Ex 10.3, 7 - Find equation of line parallel to 3x - 4y + 2 = 0 - Two lines // or/and prependicular

Ex 10.3, 7 - Chapter 10 Class 11 Straight Lines - Part 2
Ex 10.3, 7 - Chapter 10 Class 11 Straight Lines - Part 3 Ex 10.3, 7 - Chapter 10 Class 11 Straight Lines - Part 4

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Ex10.3, 7 Find equation of the line parallel to the line 3x – 4y + 2 = 0 and passing through the point (–2, 3). Let the equation of line AB be 3x – 4y + 2 = 0 & let point P be P(–2, 3) Let line CD be parallel to line AB & passing through the point P(–2,3) We have to find the equation of line CD We know that if two lines are parallel then their slopes are equal , Since line CD is parallel to line AB Thus, Slope of line CD = Slope of line AB Finding slope of line AB 3x − 4y + 2 = 0 3x + 2 = 4y (3𝑥 + 2)/4 = y (3/4)x + 2/4 = y (3/4)x + 1/2 = y y = (3/4)x + 2/4 This equation is of the form y = mx + c where m is the slope, Thus, Slope of line AB = 3/4 Now, from (1) Slope of line CD = Slope of line AB ∴ Slope of line CD = 3/4 Equation of a line passing through a point (x0, y0) & having slope m is (y – y0)= m(x – x0) Equation of a line CD passing through point P(-2,3) & having slope 3/4 is (y – y0)= m(x – x0) Putting values (y − 3) = 3/4(x – (–2)) (y − 3) = 3/4(x + 2) 4(y − 3) = 3 (x + 2) 4y − 12 = 3x + 6 − 12 − 6 = 3x − 4y 3x − 4y = − 12 − 6 3x − 4y = − 18 3x + 4y + 18 = 0 Thus, the required equation of line is 3x + 4y + 18 = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.