1. Chapter 5 Class 11 Complex Numbers
2. Serial order wise
3. Miscellaneous

Transcript

Misc 6 Solve the equation 3๐ฅ2 โ 4๐ฅ + 20/3 = 0 3๐ฅ2 โ 4๐ฅ + 20/3 = 0 Multiplying both sides by 3 3 ร (3๐ฅ2 โ 4๐ฅ "+ " 20/3) = 3 ร 0 3 ร 3x2 โ 3 ร 4x + 3 ร 20/3 = 0 9๐ฅ2 โ 12๐ฅ + 20 = 0 The above equation is of the form ๐๐ฅ2 + ๐๐ฅ + ๐ = 0 Where a = 9, b = โ12, and c = 20 x = (โ๐ยฑโ( ๐^2 โ4๐๐ ))/2๐ = (โ(โ12) ยฑ โ((โ12)^2 โ 4 ร 9 ร 20))/(2 ร 9) = (12 ยฑ โ(144 โ720))/18 = (12 ยฑ โ(โ576))/18 = (12 ยฑ โ(โ1 ร 576))/18 = (12 ยฑ โ(โ1 ) ร โ( 576))/18 = (12 ยฑ ๐ ร โ( 576))/18 = (12 ยฑ ๐ ร โ( 242))/18 = (12 ยฑ ๐ ร 24)/18 = (6(2 ยฑ ๐ ร 4))/18 = ((2 ยฑ ๐ ร 4))/3 = ((2 ยฑ ๐4))/3 Thus, ๐ฅ = ((2 ยฑ ๐4))/3

Miscellaneous

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.