Ex 5.3, 7 - Solve root 2 x2 + x + root2 = 0 - Class 11 - Ex 5.3

  1. Chapter 5 Class 11 Complex Numbers
  2. Serial order wise
Ask Download

Transcript

Ex5.3, 7 Solve the equation โˆš2x2 + x + โˆš2 = 0 โˆš2x2 + x + โˆš2 = 0 The above equation is of the form ๐‘Ž๐‘ฅ2 + ๐‘๐‘ฅ + ๐‘ = 0 Where a = โˆš2 , b = 1, and c = โˆš2 ๐‘ฅ = (โˆ’๐‘ ยฑ โˆš( ๐‘^2 โˆ’ 4๐‘Ž๐‘ ))/2๐‘Ž ๐‘ฅ = (โˆ’1 ยฑ โˆš((1)^2 โˆ’ 4 ร— โˆš(2 )ร— โˆš2) )/(2 ร—โˆš2) = (โˆ’1 ยฑ โˆš(1 โˆ’ 4 ร— 2))/(2โˆš2) = (โˆ’1 ยฑ โˆš(1 โˆ’ 8))/(2โˆš2) = (โˆ’1 ยฑ โˆš(โˆ’7))/(2โˆš2) = (โˆ’1 ยฑ โˆš(โˆ’1 ร— 7))/(2โˆš2) = (โˆ’1 ยฑ โˆš7 ๐‘–)/(2โˆš2) Thus, ๐‘ฅ = (โˆ’1 ยฑ โˆš7 ๐‘–)/(2โˆš2)

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.
Jail