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Ex 3.2, 4 - Find values of other five functions if sec x = 13/5 - Ex 3.2

  1. Chapter 3 Class 11 Trigonometric Functions
  2. Serial order wise
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Ex3.2, 4 Find the values of other five trigonometric functions if sec x = 13/5 , π‘₯ lies in fourth quadrant. Since x lies in the lVth Quadrant Where cos will be positive But sin and tan will be negative We know that 1 + tan2x = sec2x 1 + tan2x = (13/5)^2 tan2x = (13/5)^2 – 1 = 169/25 – 1 = (169 βˆ’ 25)/25 tan2x = 144/25 tan x = Β± √(144/25) tan x = Β± 12/5 Since x is in lVth Quadrant tan x is negative in lVth Quadrant ∴ tan x = (βˆ’12)/5 cot x = 1/tπ‘Žπ‘›β‘π‘₯ = 1/(" " (βˆ’12)/5) = (βˆ’5)/12 cos x = 1/s𝑒𝑐⁑π‘₯ = 1/(" " 13/5) = 5/13 tan x = sin⁑π‘₯/cos⁑π‘₯ sin x = (tan x) Γ— (cos x ) = (βˆ’12)/5 Γ— 5/13 = (βˆ’12)/13 cosec x = 1/sin⁑π‘₯ = (βˆ’13)/12

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