1. Chapter 2 Class 11 Relations and Functions
2. Serial order wise

Transcript

Ex 2.3, 4 The function ‘t’ which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by . t(C) = 9/5 C+ 32 . Find (i) t (0) (ii) t (28) (iii) t (-10) Given t(C) = 9/5 C + 32 Putting C = 0, t(0) = (9 )/5 × (0) + 32 = 0 + 32 = 32 We know that t(C) = 9/5 C + 32 Putting C = 28, t(28) = (9 )/5 × (28) + 32 = (252 )/5 + 32 = (252 + 32 × 5)/5 = (252 + 160)/5 = 412/5 Given t(C) = 9/5 C + 32 Putting C = -10, t(0) = (9 )/5 × ( – 10) + 32 = 9 × ( – 2) + 32 = – 18 + 32 = 14 Ex 2.3, 4 The function ‘t’ which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by . t(C) = 9/5 C+ 32 . Find (iv) The value of C, when t(C) = 212 Given t(C) = 9/5 C+ 32 Putting t(C) = 212 212 = 9/5 C+ 32 212 – 32 = 9/5 C 9/5 C = 212 – 32 9/5 C= 180 9C = 180 × 5 C = (180 × 5)/9 C = 100

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