Ex 10.2, 10 - Chapter 10 Class 10 Circles
Last updated at April 16, 2024 by Teachoo
Theorem 10.1: Tangent perpendicular to radius (proof type)
Chapter 10 Class 10 Circles
Concept wise
- Number of tangents
- Theorem 10.1: Tangent perpendicular to radius (numerical type)
-
Theorem 10.1: Tangent perpendicular to radius (proof type)
- Theorem 10.2: Equal tangents from external point (numerical type)
- Theorem 10.2: Equal tangents from external point (proof type)
Transcript
Ex 10.2,10 Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre. Given: A circle with center O. Tangents PA and PB drawn from external point P To prove: APB + AOB = 180 Proof: In quadrilateral OAPB OAP + APB + OBP + AOB = 360 Putting values of angles 90 + APB + 90 + AOB = 360 180 + APB + AOB = 360 APB + AOB = 360 180 APB + AOB = 180 Hence proved
