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Ex 8.1, 4 - Given 15 cot A = 8, find sin A and sec A. - Ex 8.1

  1. Chapter 8 Class 10 Introduction to Trignometry
  2. Serial order wise
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Ex 8.1, 4 Given 15 cot A = 8, find sin A and sec A. 15 cot A = 8 cot A = 8/15 Now, tan A = 1/cotโก๐ด = 1/(8/15) = 15/8 Hence, tan A = 15/8 tan A = 15/8 (๐‘ ๐‘–๐‘‘๐‘’ ๐‘œ๐‘๐‘๐‘œ๐‘ ๐‘–๐‘ก๐‘’ ๐‘ก๐‘œ โˆ ๐ด)/(๐‘ ๐‘–๐‘‘๐‘’ ๐‘Ž๐‘‘๐‘—๐‘Ž๐‘๐‘’๐‘›๐‘ก ๐‘ก๐‘œโˆ ๐ด) = 15/8 ๐ต๐ถ/๐ด๐ต=15/8 Let BC = 15x & AB = 8x Finding AC using Pythagoras theorem, (Hypotenuse)2 = (Height)2 + (Base)2 AC2 = AB2 + BC2 AC2 = (8x)2 + (15x)2 AC2 = 64 x2 + 225 x2 AC2 = 289 x2 AC = 17x Now, we need to find sin A & sec A

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