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Ex 6.3, 4 - QR / QS  = QT / PR and angle 1 = 2. Show that - Ex 6.3

  1. Chapter 6 Class 10 Triangles
  2. Serial order wise
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Ex 6.3, 4 In figure, ๐‘„๐‘…/๐‘„๐‘† = ๐‘„๐‘‡/๐‘ƒ๐‘… and โˆ 1 = โˆ 2. Show that ฮ”PQS โˆผ ฮ”TQR. Given : ๐‘„๐‘…/๐‘„๐‘†=๐‘„๐‘‡/๐‘ƒ๐‘… โˆ  1= โˆ  2 To prove: ฮ”PQS โˆผ ฮ”TQR Proof: Given โˆ  1 = โˆ  2 PR = QP Given ๐‘„๐‘…/๐‘„๐‘†=๐‘„๐‘‡/๐‘ƒ๐‘… Putting (1) ๐‘„๐‘…/๐‘„๐‘†=๐‘„๐‘‡/๐‘„๐‘ƒ In ฮ”PQS and ฮ”TQR โˆ  ๐‘ƒ๐‘„๐‘†= โˆ  ๐‘‡๐‘„๐‘… & ๐‘„๐‘…/๐‘„๐‘†=๐‘„๐‘‡/๐‘„๐‘ƒ โˆด ฮ”PQS โˆผ ฮ”TQR Hence proved

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