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Ex 5.1, 2 - Write first four terms of AP when first term a - Checking if AP or not and finding a, d


  1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise
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Ex 5.1 ,2 Write first four terms of the A.P. when the first term a and the common difference d are given as follows (i) a = 10, d = 10 First term = a = 10 Common difference = d = 10 Second term = First term + Common difference = 10 + 10 = 20 Third term = Second term + Common difference = 20 + 10 = 30 Fourth term = Third term + Common difference = 30 + 10 = 40 Hence, first four term of AP 10, 20, 30, 40 …… Ex 5.1, 2 Write first four terms of the A.P. when the first term a and the common difference d are given as follows (ii) a = − 2, d = 0 First term = a = – 2 Common difference = d = 0 Second term = First term + Common difference = – 2 + 0 = – 2 Third term = Second term + Common difference = – 2 + 0 = – 2 Fourth term = Third term + Common difference = – 2 + 0 = – 2 Hence , first four term of AP = – 2, – 2, – 2, – 2 Ex 5.1 ,2 Write first four terms of the A.P. when the first term a and the common difference d are given as follows (iii) a = 4, d = − 3 First term = a = 4 Common difference = – 3 Second term = First term + Common difference = 4 + ( – 3) = 4 – 3 = 1 Third term = Second term + Common difference = 1 + ( – 3) = 1 – 3 = – 2 Fourth term = third term + common difference = – 2 + ( – 3) = – 2 – 3 = – 5 Hence, first 4 terms of AP are 4, 1, – 2, – 5, Ex 5.1 ,2 Write first four terms of the A.P. when the first term a and the common difference d are given as follows (iv) a = − 1 d =  1/2 First term = a = – 1 Common difference = d = 1/2 Second term = First term + common difference = – 1 + 1/2 = (− 2 + 1)/2 = (−1)/2 Third term = Second term + common difference = – 1/2 + 1/2 = 0 Fourth term = third term + common difference = 0 + 1/2 = (0 + 1)/2 = 1/2 Hence first four terms of AP are – 1, (− 1)/2 , 0 , 1/2 Ex 5.1 ,2 Write first four terms of the A.P. when the first term a and the common difference d are given as follows (v) a = − 1.25, d = − 0.25 first term = a = – 1.25 Common difference = d = – 0.25 Second term = first term + common difference = – 1.25 + ( – 0.25) = – 1.25 – 0.25 = – 1.50 Third term = second term + common difference = – 1.50 + ( – 0.25) = – 1.50 – 0.25 = – 1.75 Fourth term = third term + common difference = – 1.75 + ( – 0.25) = – 1.75 – 0.25 = – 2.00 Hence first 4 hence of AP are 0, – 1.50, – 1.75, – 2.00

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