The point on x axis equidistant from I and E is

(a) (1/2, 0)    (b) (0,  (-1)/2)     (c) ((-1)/2, 0)       (d) (0,  1/2)

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Question 48 The point on x axis equidistant from I and E is (a) (1/2, 0) (b) (0, (−1)/2) (c) ((−1)/2, 0) (d) (0, 1/2) Since required point is on x-axis It’s y-coordinate is 0 Let X (x, 0) be the required point Since point X (x, 0) is equidistant from points I (−1, 1) and E (2, 1) IX = EX √(( 𝑥 −(−1) )2+(1−0)2) = √((𝑥−2)2+(0−1)2) √(( 𝑥+1 )2+12) = √((𝑥−2)2+12) Squaring both sides ( 𝑥+1)2+12 = ( 𝑥−2)2+12 ( 𝑥+1)2 = ( 𝑥−2)2 𝑥^2+1+2𝑥=𝑥^2+4−4𝑥 1+2𝑥=4−4𝑥 4𝑥+2𝑥=4−1 6𝑥=3 𝑥=3/6 𝒙=𝟏/𝟐 ∴ Required coordinates = (x, 0) = (𝟏/𝟐, 𝟎) So, the correct answer is (a)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.