CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

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Question 31 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards

Last updated at April 16, 2024 by

The equation of the perpendicular bisector of line segment joining points A (4, 5) and B (−2, 3) is

(a) 2x – y + 7 = 0   (b) 3x + 2 y – 7 = 0

(c) 3x – y – 7 =0       (d) 3x + y – 7 = 0

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Question 31 The equation of the perpendicular bisector of line segment joining points A (4, 5) and B (−2, 3) is (a) 2x – y + 7 = 0 (b) 3x + 2 y – 7 = 0 (c) 3x – y – 7 =0 (d) 3x + y – 7 = 0 Let Line l be the perpendicular bisector of AB And let it intersect AB at point P Let point P be any point on Line l By symmetry AP = BP √(( 𝑥 −4 )2+(𝑦−5)2) = √(( 𝑥 −(−2))2+(𝑦−3)2) √(( 𝑥 −4 )2+(𝑦−5)2) = √(( 𝑥+2)2+(𝑦−3)2) Squaring both sides ( 𝒙 −𝟒)𝟐+(𝒚−𝟓)𝟐 = ( 𝒙+𝟐)𝟐+(𝒚−𝟑)𝟐 𝑥^2+16−8𝑥+𝑦^2+25−10𝑦=𝑥^2+4+4𝑥+𝑦^2+9−6𝑦 16−8𝑥+25−10𝑦=4+4𝑥+9−6𝑦 −8𝑥−10𝑦+41=4𝑥−6𝑦+13 0 =4𝑥−6𝑦+13+8𝑥+10𝑦−41 0 =4𝑥+8𝑥−6𝑦+10𝑦+13−41 0 =12𝑥+4𝑦−28 12𝑥+4𝑦−28=0 Dividing by 4 both sudes 𝟑𝒙+𝒚−𝟕=𝟎 So, the correct answer is (d)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.