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Ex 7.1, 6 - In figure, AC = AE, AB = AD and ∠BAD = ∠EAC - SAS

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Ex 7.1, 6 In the given figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. Given: AC = AE AB = AD ∠ BAD = ∠ EAC To prove: BC = DE Proof: Given that ∠BAD = ∠EAC ∠BAD + ∠DAC = ∠EAC + ∠DAC ∠BAC = ∠DAE In ΔABC and ΔADE, AB = AD ∠BAC = ∠DAE AC = AE ∴ ΔABC ≅ ΔADE ∴ BC = DE Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
  • ASHOK PRASAD KANOO's image
    ASHOK PRASAD KANOO
    Sept. 26, 2017, 9:30 a.m.
    Mam, can we right  angle EAD in question number 6 exercise 7.1 Triangle 9class please give me the answer fast . My FA2 is coming 


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