Ex 7.1, 6 - In figure, AC = AE, AB = AD and ∠BAD = ∠EAC - SAS

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Ex 7.1, 6 In the given figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. Given: AC = AE AB = AD ∠ BAD = ∠ EAC To prove: BC = DE Proof: Given that ∠BAD = ∠EAC ∠BAD + ∠DAC = ∠EAC + ∠DAC ∠BAC = ∠DAE In ΔABC and ΔADE, AB = AD ∠BAC = ∠DAE AC = AE ∴ ΔABC ≅ ΔADE ∴ BC = DE Hence proved

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