Ex 6.3, 5 - In figure, if PQ ⊥ PS, PQ || SR, ∠SQR = 28° - Ex 6.3

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Ex 6.3, 5 In the given figure, if PQ ⊥ PS, PQ || SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y. Since PQ || SR and QR is a transversal. ∠PQR = ∠QRT x + 28° = 65° x = 65° − 28° x = 37° In ΔSPQ, ∠ SPQ + x + y = 180° 90° + 37° + y = 180° y = 180° − 127° y = 53° Thus, x = 37° and y = 53°

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