Last updated at May 29, 2018 by Teachoo

Transcript

Ex 6.1, 6 It is given that XYZ = 64 and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ZYP, find XYQ and reflex QYP. XYP is a straight line, XYZ + ZYP = 180 ZYP = 180 XYZ ZYP = 180 64 ZYP = 116 Since YQ bisects ZYP ZYQ = QYP = 1/2 ZYP = 1/2 116 = 58 XYQ = XYZ + ZYQ = 64 + 58 = 122 We have to find Reflex QYP Reflex QYP = 360 QYP Reflex QYP = 360 58 = 302

Class 9

Important Questions for Exam - Class 9

- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
- Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.