Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 10 Check whether the polynomial q(t) = 4t3 + 4t2 – t – 1 is a multiple of 2t + 1. Finding remainder when 4t3 + 4t2 – t – 1 is divided by 2t + 1 Step 1: Put Divisor = 0 2t + 1 = 0 2t = –1 t = (−1)/2 Step 2: q(t) = 4t3 + 4t2 – t – 1 Putting t = (−1)/2 q((−1)/2) = 4 ((−1)/2)^3 + 4 ((−1)/2)^2 – ((−1)/2) – 1 = − 4 (1/8) + 4 (1/4) + 1/2 − 1 = − 1/2 + 1 + 1/2 − 1 = 0 Thus, remainder = q((−1)/2) = 0 Since, remainder is 0 Thus, 4t3 + 4t2 – t – 1 is a multiple 2t + 1

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.