Answer of this question

Hi Sahil, 

The text version of the answer is -

Find the principal value of  tan-1(tan⁡〖2π/3〗 )

Let y = tan-1(tan⁡〖2π/3〗 )

tan y =〖 tan〗⁡〖2π/3〗

tan y = tan (120°)

We know that range of principal value of tan-1 is

 (− π/2 , π/2 ) i.e. (− 90° ,90°)

Hence y = 120° not possible

Now,

  tan y = tan (120°)

  tan y = tan (180° – 60°)

  tan y =  – tan (60°)

  tan y =  tan (–60°)

  tan y = tan (–60  ×  π/180)

  tan y = tan ((-π)/3)

Hence,  y = (-π)/3

Which is in the range of principal value of tan-1 i.e. ((-π)/2, π/2)

Hence, tan-1(tan⁡〖2π/3〗 ) = y = (-π)/3

Notes - 

(As tan (180 – θ) = – tan θ)

(As tan (–θ) = – tan θ)

Written on Jan. 26, 2017, 11:23 a.m.